Asked by Zach
I am not sure if I calculated the exact molarity of the potassium permanganate. I multiplied the molarity of the potassium permanganate by the liters of potassium permanganate used in the titration and divided it by the total liters of solution. I don't know if that if how it is done or not.
(0.125M)(0.0378L)/0.0828L= 0.057M KMnO4
(0.125M)(0.0378L)/0.0828L= 0.057M KMnO4
Answers
Answered by
DrBob222
See your post above.
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