Asked by Sasha
I have already calculated the volume of ethyl alcohol need to dissolve 0.300 g of sulfanilamide at 78 degrees Celsius. I got 1.429 mL ethyl alcohol. My question is: how do I calculate how many grams of sulfanilamide will remain dissolved in the mother liquor (ethyl alcohol) after the mixture has cooled to O.O degrees Celsius? Given that the solubility of sulfanilamide at 78 degrees Celsius is 210 mg/mL, and at 0.0 degrees Celsius is 14 mg/mL. This is for Pre-Lab calculations. Can anyone show me the dimensional analysis involved? Thank you!
Answers
Answered by
DrBob222
For the first one, which you have done correctly, it is
210 mg/mL x ? mL = 300 mg
? mL ethanol - 1.429 mL needed.
When it cools to zero C, the solubility is
14 mg/mL x 1.429 mL = ? mg dissolved.
210 mg/mL x ? mL = 300 mg
? mL ethanol - 1.429 mL needed.
When it cools to zero C, the solubility is
14 mg/mL x 1.429 mL = ? mg dissolved.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.