How many milliliters of a stock solution of 6.00 M HNO3 would you have to use to prepare 0.190 L of 0.490 M HNO3?
I used the equation M1V1=M2V2
6M*V1 = 0.190L*0.490 M
lead me to this V1=0.190L*0.490M/6.00 M
=0.0931 L per M/6.00M
=0.0155166L
0.0155166L/1000mL= 0.155166L
1 answer
0.0155L * 1000mL/L = 15.5mL
2 answers