How many milliliters of .100 M HNO3 are needed to neutralize 58.5 mL of .0100 Al(0H)3?

Answer 1

3HNO3 + Al(OH)3 ==> Al(NO3)3 + 3H2O
How many mols Al(OH)3 do you have? That is M x L = ?

So how many mols HNO3 are needed to neutralize it. The equations tells you moles HNO3 = 3* moles Al(OH)3.

Then M HNO3 = moles HNO3/L HNO3.
You have M and moles solve for L HNO3 an convert to mL.

Answer 2

17.6 mL