Specific heat of ice is
2100J/kg°C
How many joules of heat are required to melt 20.0 kg of ice at 0°C?
3 answers
Would I need to multiply 2100*20.0
Nevermind
Its
(20.0)(3.35*10^5)=6700000
Or 6.70*10^6
3.35*10^5 was the heat fusion of ice
Its
(20.0)(3.35*10^5)=6700000
Or 6.70*10^6
3.35*10^5 was the heat fusion of ice
1 answer