ben green

A snowmobile is pulling a large sled across a snow-covered field. The weight of the sled is 3560 N. If the coefficient of friction of the sled is 0.12, what is the pulling force supplied by the snowmobile?

A truck with a mass of 14,0 00 kg is pushed with a force of 9200 N. If the frictional force is 2150 N what is the truck’s acceleration?

A ball of mass 0.50 kg is thrown straight up at 6.0 m/s. (a)What is the initial momentum of the ball? (b) What is the momentum of the ball at its peak? (c)What is the momentum of the ball as it hits the ground

How much work is done lifting a wrecking ball 6.50 m above the ground? So the formula for this problem would be: W=fs F=200kg S=6.50m (200)(6.50)=1300

The handle of a vegetable wagon makes an angle of 25.0° If the peddler exerts a force of 35.0 lb along the handle, how muchwork does the peddler do in pulling the cart 1.00 mi? Is this correct? 35.0*1.00coseine25.0degrees=31.720

How many joules of heat are required to melt 20.0 kg of ice at 0°C?

I need help in finding good online sources for my essay. The topic and question is; why do community college students drop out?

would I need to convert the mass to another unit? and do I divide 7050 by the mass 14,000?

A)P=mv >> 0.50 X 6.0 = 3 B)Peak V=0 C)final momentum = -3

I forgot to add the wrecking ball weighs 200kg

Dont know if its like this: 35.0*9.80*1.00cos25.0 = 310.86

So would this be the setup? (1.3x10^-5/C°)(8.25m)(-105°C)=-0.01m

Specific heat of ice is 2100J/kg°C

Would I need to multiply 2100*20.0

Nevermind Its (20.0)(3.35*10^5)=6700000 Or 6.70*10^6 3.35*10^5 was the heat fusion of ice