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ben green
Questions (8)
I need help in finding good online sources for my essay. The topic and question is; why do community college students drop out?
1 answer
560 views
How many joules of heat are required to melt 20.0 kg of ice at 0°C?
3 answers
638 views
The handle of a vegetable wagon makes an angle of 25.0° If the peddler exerts a force of 35.0 lb along the handle, how muchwork
3 answers
919 views
How much work is done lifting a wrecking ball 6.50 m above the ground?
So the formula for this problem would be: W=fs F=200kg
2 answers
848 views
How much work is done in lifting 450 lb of cement 75 ft above the ground?
So basically its W=fs (450lb)(75ft)=33750lb
0 answers
616 views
A ball of mass 0.50 kg is thrown straight up at 6.0 m/s. (a)What is the initial momentum of the ball? (b) What is the momentum
2 answers
2,755 views
A truck with a mass of 14,0 00 kg is pushed with a force of 9200 N. If the frictional force is 2150 N what is the truck’s
2 answers
596 views
A snowmobile is pulling a large sled across a snow-covered field. The weight of the sled is 3560 N. If the coefficient of
1 answer
1,120 views
Answers (8)
Nevermind Its (20.0)(3.35*10^5)=6700000 Or 6.70*10^6 3.35*10^5 was the heat fusion of ice
Would I need to multiply 2100*20.0
Specific heat of ice is 2100J/kg°C
So would this be the setup? (1.3x10^-5/C°)(8.25m)(-105°C)=-0.01m
Dont know if its like this: 35.0*9.80*1.00cos25.0 = 310.86
I forgot to add the wrecking ball weighs 200kg
A)P=mv >> 0.50 X 6.0 = 3 B)Peak V=0 C)final momentum = -3
would I need to convert the mass to another unit? and do I divide 7050 by the mass 14,000?
