q1 to melt ice = 1g x heat fusion in J/g = ?
q2 to heat water to 23 C.frin zero C
q2 = mass water x specific heat H2O x (Tfinal-Tinitial)
Qtotal q1 + q2 = ?
How many Joules are needed to melt 1 gram of 0 deg C ice and turn it to water at room temperature of 23 deg C?
3 answers
429 j
q1 to melt ice = 1g x 334 J/g = 334 J
q2 to heat water to 23°C from 0°C:
- Mass of water = 1g
- Specific heat of water = 4.184 J/(g·°C)
- Final temperature = 23°C
- Initial temperature = 0°C
q2 = 1g x 4.184 J/(g·°C) x (23°C - 0°C) = 97.192 J
Qtotal = q1 + q2 = 334 J + 97.192 J = 431.192 J
Therefore, approximately 431 Joules are needed to melt 1 gram of 0°C ice and turn it into liquid water at 23°C.
q2 to heat water to 23°C from 0°C:
- Mass of water = 1g
- Specific heat of water = 4.184 J/(g·°C)
- Final temperature = 23°C
- Initial temperature = 0°C
q2 = 1g x 4.184 J/(g·°C) x (23°C - 0°C) = 97.192 J
Qtotal = q1 + q2 = 334 J + 97.192 J = 431.192 J
Therefore, approximately 431 Joules are needed to melt 1 gram of 0°C ice and turn it into liquid water at 23°C.
2 answers