what number of joules needed to turn 325g of water at 100 degree c to steam at 100 degree c
2 answers
q = mass water x heat vaporization
q = (325 g)(2260 J/g)
*grams cancel out*
q = 734500 J
q = 7.345*10^5 J
*grams cancel out*
q = 734500 J
q = 7.345*10^5 J