How many joules are needed to heat 8.50 grams of ice from -10.0 degrees C to 25.0 degrees C?

Answer 1

q1 = heat necessary to change ice from -10 to zero = mass x specific heat ice x (Tfinal - Tinitial) where Tfinal is zero and Tinitial is -10.

q2 = heat necessary to melt ice but stay at zero = mass x heat fusion of ice.

q3= heat necessary to heat water at zero to 25 C. = mass x specific heat water x (25-0).
total = q1 + q2 + q3.
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