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How many grams of water would you add to 1.00 kg of 1.48 m CH3OH(aq) to reduce the molality to 1.00 m CH3OH. Use two sig figs.

I get 4.8 * 10^2 grams and its not right. I want to put this up here again to see if there are any errors that could have possibly been made

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I believe Bob Pursley has figured out the problem. I think he will post a response.

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