0.02 moles is required=0.5L*0.04 M
500mL=0.5L
0.02 moles*(39.997g/mole)=???
(???/500)*100= w/v %
How many grams of solid NaOH are required to prepare 500 ml of a
0.04 M solution? (b) Express the concentration of this solution in terms of
N, g/liter, % w/v?
3 answers
Only 1 equivalent. So, M is equal to N
g/L= ???/0.5L
Answer should have only one significant figure, but you can include 3.
g/L= ???/0.5L
Answer should have only one significant figure, but you can include 3.
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