how many grams of solid NaOH are required to prepare 200.0 mL of a .050 M solution?
2 answers
mL x M = mL x M
200/1000=0.2
0.2*0.05=0.01
0.01*40=0.4g
0.2*0.05=0.01
0.01*40=0.4g
2 answers