CN^- + HOH ==> HCN + OH^-
Kb = (Kw/Ka) = (HCN)(OH^-)/(CN^-)
You want pH to be 10 so pOH must be 4. Convert that to (OH^-) and plug into the Kb expression I have above. Solve for (CN^-) and the answer will be in molarity. Convert to grams NaCN/L of solution, then convert to 250 mL.
how many grams of NaCN would you need to dossolve in enough water to make exactly 250.0mL of soultion with pH of 10.00?
2 answers
7.35 x 10^-3
1 answer