How many grams of KMnO4 Is required to prepare 1.0 liter of a solution of 1.5 M KMnO 4?

Answer 1

The molar mass of KMnO4 is 158.034 g/mol.

To prepare 1.0 liter of a solution of 1.5 M KMnO4, we need to calculate the number of moles of KMnO4 required:

1.5 M = 1.5 mol/L

1.5 mol/L x 1.0 L = 1.5 mol

Now, we can calculate the mass of KMnO4 required using the molar mass:

1.5 mol x 158.034 g/mol = 237.051 g

Therefore, 237.051 grams of KMnO4 is required to prepare 1.0 liter of a solution of 1.5 M KMnO4.