To solve this problem, we can use the formula:
moles = concentration x volume
First, we need to calculate the number of moles of HNO3 required to prepare the solution:
moles = 0.6601 mol/L x 0.5 L = 0.33005 mol
Next, we can use the molar mass of HNO3 to convert moles to grams:
molar mass of HNO3 = 63.01 g/mol
grams = moles x molar mass = 0.33005 mol x 63.01 g/mol = 20.79 g
Therefore, 20.79 grams of HNO3 are required to prepare a 500 mL of 0.6601 M HNO3 solution.
How many grams of HNO3 are required to prepare 500Ml of a 0.6601M HNO3 Solution?
1 answer