How many grams of HNO3 are required to prepare 500Ml of a 0.601M HNO3 Solution?

Answer 1

First, we need to calculate the number of moles of HNO3 in 500mL of 0.601M solution:

0.601 moles/L x 0.5 L = 0.3005 moles

Next, we can use the molar mass of HNO3 (63.01 g/mol) to convert moles to grams:

0.3005 moles x 63.01 g/mol = 18.95 g

Therefore, 18.95 grams of HNO3 are required to prepare 500mL of a 0.601M solution.