How many grams of CO2 are produced when 11.47 moles hexane combust?

Question

My work:I balanced the equation like so C6H14 + 19/2 O2 ==> 6CO2 + 7H2O

My teacher taught us the 19/2 was valid

My work:

11.47 mol C6H14 * 6 CO2/1 mol C6H14 * 44g/mol/1 mol CO2 = 3, 028 g of CO2

Answer 1

I agree with your answer. As for the 19/2, I think many profs will not allow it but I don't see anything wrong with it.

Answer 2

Agreed. In high school I was taught something else. Like multiply every thing by 2. To get a whole number.

Thank you for your help