64g AuCl3 = 0.21 moles
The equation is not balanced; fix that to see how many moles of Cl2 to expect
Convert that to grams.
How many grams of chlorine can be liberated from the decomposition of 64.0 g. of AuCl3 by this reaction:
AuCl3 ---> Au + Cl2
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3 answers