Write the balanced equation.
2HCl ==> H2 + Cl2
Convert 25 g HCl to moles. #moles = grams/molar mass.
Using the coefficients in the balanced equation, convert moles HCl to moles Cl2.
Convert moles Cl2 to grams. # grams = moles x molar mass. This # grams is the theoretical yield.
Now calculate percent yield.
% yield = [13.6/theoretical yield]*100
calculate the percent yield of Cl2 in the electrolytic decomposition of hydrogen chloride if 25 g of HCl produces 13.6 of chlorine gas.
3 answers
2HCl=H2+Cl2
2mol:1mol:1mol
Mole of HCl=Mass/molar mass=25/36.46=0.69mol
2/0.69=1/x x=0.345mol of Cl2
0.345*(35.45*2)=24.46gram
Percent yield=(13.6/24.46)*100%=55.60%
2mol:1mol:1mol
Mole of HCl=Mass/molar mass=25/36.46=0.69mol
2/0.69=1/x x=0.345mol of Cl2
0.345*(35.45*2)=24.46gram
Percent yield=(13.6/24.46)*100%=55.60%
%yield= Practical yield/ theoretical yield
WE are calculating the theoretical yield,
2 mols of HCl gives 1mol of Cl2 Hense,
mols of HCl= 25/36.46 = 0.685 mols
mols of cl2 produced =0.685/2 = 0.342 mols
--> theoretical yeild = 0.342*70.90 = 24.30grams
Now % yield of cl2 = 13.6/24.30 = 55.96% of cl2
WE are calculating the theoretical yield,
2 mols of HCl gives 1mol of Cl2 Hense,
mols of HCl= 25/36.46 = 0.685 mols
mols of cl2 produced =0.685/2 = 0.342 mols
--> theoretical yeild = 0.342*70.90 = 24.30grams
Now % yield of cl2 = 13.6/24.30 = 55.96% of cl2