MrCooL

%yield= Practical yield/ theoretical yield WE are calculating the theoretical yield, 2 mols of HCl gives 1mol of Cl2 Hense, mols of HCl= 25/36.46 = 0.685 mols mols of cl2 produced =0.685/2 = 0.342 mols --> theoretical yeild = 0.342*70.90 = 24.30grams Now...

The balanced combustion process for carbon monoxide is as follows, 2CO + O2 --> 2CO2 delta H = delta H (products) - delta H (reactants) = 2(743) - [2(1073) + 1(496)] = -1156 kJ/mol of reaction of CO for 1mol of CO = -1156/2 = -578 kJ/mol