All you need to do is convert to moles AuCL3 and then use the mole ratio and convert back to grams Cl2
64.0*(1 mol/233g)*(3 mol Cl2/2mol AuCl3)*70.906gCl2=
29.214
how many grams of chlorine can be liberated from the decomposition of 64.0g of AuCl3 by this reaction
2 AuCl3----> 2 Au + 3cl2
2 answers
wrong
1 answer