The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, 1.0 L of carbon dioxide gas at STP would be equivalent to 1.0/22.4 = 0.0446 moles of carbon dioxide.
Now, we can calculate the mass of 0.0446 moles of carbon dioxide using the molar mass of carbon dioxide:
0.0446 moles * 44.01 g/mol = 1.96 g
Therefore, the correct answer is 1.96 g of carbon dioxide gas in a 1.0-L balloon at STP.
How many grams of carbon dioxide gas (molar mass = 44.01 g/mol) are in a 1.0-L balloon at STP
O 0.509 g
0 1.96 g
O 22.4 g
O 44.0 g
1 answer
4 answers