Given the following equation : 2Al+6HCl 2AlCl 3 +3H 2 If 3.00 grams of H 2 were produced, how many grams of Al reacted ? (Molar mass of Al = 26.98g / (mol) , molar mass of H 2 = 2.016 g/mol)

Answer 1

I have rewritten the equation to make it easier to read and understand.
2Al + 6HCl ==> 2AlCl3 + 3H2

How many mols H2 are in 3 g H2? That's mols = grams/molar mass = 3.00/2 = 1.5.
Convert 1.5 mols H2 to mols Al. That's done by using the coefficients in the balanced equation; i.e., 1.5 mols H2 x (2 mol Al/3 mol H2) = 1.5 x 2/3 = ?
Now convert mols Al to grams. g Al = mols Al x atomic mass Al = ?
Post your work if you get stuck.

Answer 2

13.1

Answer 3

i got 3.78

Answer 4

26.8