How many grams of CaCl2 would be dissolved in 1.1 L of a 0.17 M solution of CaCl2?

Answer 1

.17 *1.1 = .187 mols

CaCl2 = 111 grams/mol
(40 + 2*35.5 )

.187 mol (111 g/mol) = 20.8 grams

Answer 2

i got this one wrong