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How many grams of bismuth (III) chloride can be produced from 575 mL of chlorine gas at STP when reacting with excess bismuth metal?

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2Bi + 3Cl2 ==> 2BiCl3
mols Cl2 = 575/22,400 = ?
Using the coefficients in the balanced equation, convert mols Cl2 to mols Bi.
Now convert mols Bi to grams. g Bi = mols Bi x atomic mass Bi.

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