How many grams of ammonia can be produced from 1.33 grams of nitrogen trichloride?

Question

Nitrogen tricholoride gas reacts with water to produce ammonia and hypochlorous acid according to the following equation:

NCl3 + 3H2O → NH3 + 3HClO

Answer 1

To determine the amount of ammonia produced, we need to use stoichiometry and the molar masses of the compounds involved.

1. Write out the balanced chemical equation:

NCl3 + 3H2O --> NH3 + 3HClO

2. Calculate the molar mass of NCl3:

N = 14.01 g/mol
Cl = 35.45 g/mol (we have 3 Cl atoms)
Molar mass of NCl3 = 14.01 + (35.45 x 3) = 120.92 g/mol

3. Convert the given mass of NCl3 to moles:

1.33 g NCl3 x (1 mol / 120.92 g) = 0.011 mol NCl3

4. Use the mole ratio from the balanced equation to find the moles of NH3 produced:

1 mol NCl3 produces 1 mol NH3

0.011 mol NCl3 x (1 mol NH3 / 1 mol NCl3) = 0.011 mol NH3

5. Convert the moles of NH3 to grams:

Molar mass of NH3 = 17.03 g/mol

0.011 mol NH3 x (17.03 g / 1 mol) = 0.187 g NH3

Therefore, 0.187 grams of ammonia can be produced from 1.33 grams of nitrogen trichloride.