1 mole of nitrogen (N2) reacts with 3 moles of hydrogen (H2) to produce 2 moles of ammonia (NH3).
First, we need to calculate the molar mass of ammonia (NH3):
N: 14.01 g/mol
H: 1.01 g/mol
Molar mass of NH3 = 14.01 + (3 * 1.01) = 17.04 g/mol
Now, we can calculate the number of moles of ammonia produced from 325 grams:
325 g / 17.04 g/mol = 19.07 moles of NH3
From the balanced chemical equation, we know that 1 mole of N2 reacts to produce 2 moles of NH3. Therefore, the number of moles of N2 needed is half of the moles of NH3 produced:
19.07 moles of NH3 / 2 = 9.53 moles of N2
Now, we can calculate the grams of nitrogen needed:
Molar mass of N2 = 2 * 14.01 = 28.02 g/mol
9.53 moles * 28.02 g/mol = 267.21 grams of nitrogen
Therefore, 267.21 grams of nitrogen are needed to produce 325 grams of ammonia.
Ammonia, an important source of fixed nitrogen that can be metabolized by plants, is produced using the Haber process in which nitrogen and hydrogen combine.
N2(g) + 3H2(g) --> 2NH3(g)
How many grams of nitrogen are needed to produce 325 grams of ammonia?
1 answer