How many grams of Al2(SO4)3 can be produced from 10.0g of CuSO4?

Answer 1

well, the bare-bones equation is of the form

Al2(SO4)3 + x -> 3CuSO4 + x

so, each mole of Al2(SO4)3 produces 3 moles of CuSO4.

Just convert your grams to moles, and work it from there.

Answer 2

Personally, I prefer the answer of "You can't".

Answer 3

DrBob222 may have the right of it.

And besides, my reaction "equation" is backwards. We wanted to produce the Al2(SO4)3, not use it.

But then, I'm sure you caught that, right?

Answer 4

To be honest about it I was just trying to be a smart alec! Turning CuSO4 into Al2(SO4)3 is like the alchemists who tried to turn Pb into Au.

Answer 5

What, there isn't any kind of double-replacement reaction that can swap metals like that?

Answer 6

Sure, but I read the problem as we had 10.0 g CuSO4 and nothing more; thus, the alchemist thought.