making ZnCl2
2HCl + Zn ---> ZnCl2 + H2
so I need 2 mols of HCl for every one of Zn
mol mass of Zn = about 65
13/65 = 0.2 Mol of Zn
so need 0.4 mol of HCl
How many grams of HCl is that ?
mol of HCl = 1 + 35.5 = 36.5 grams/mol
.4 * 36.5 = 14.6 grams of HCl
14.6 = 0.10 * mass of fluid in bottle of HCl
so 146 grams fluid in bottle needed
How many gram of hydrogen chloride acid containing 10% by mass of hydrogen chloride acid would be required to dissolve 13g of zinc
3 answers
Zn + 2HCl ==> ZnCl2 + H2
mols Zn = grams/atomic mass = 13 g/atomic mass = estimated 0.2 but you need a better number on ALL of these calculations.
0.2 mols Zn x (2 mols HCl/1 mol Zn) = estd 0.4 mols HCl.
g HCl = mols HCl x molar mass HCl = estd 15 grams if it were 100%. It is only 10%; therefore, about 15/0.10 = about 150 grams.
Post your work if you get stuck.
mols Zn = grams/atomic mass = 13 g/atomic mass = estimated 0.2 but you need a better number on ALL of these calculations.
0.2 mols Zn x (2 mols HCl/1 mol Zn) = estd 0.4 mols HCl.
g HCl = mols HCl x molar mass HCl = estd 15 grams if it were 100%. It is only 10%; therefore, about 15/0.10 = about 150 grams.
Post your work if you get stuck.
I don't understand the solving?