no,
number of games in one round = C(8,2) = 28
so for two rounds that would be 56
When you take 8*7 that would include cases such as
teamA vs Team B and Team B vs Team A, but that is the same game and in your first 8*7 or 56 games you have 28 such pairs.
So you must divide by 2.
In other words, you have taken the order into play, but this is not a permutation, but rather a combination.
How many games are played in a women’s soccer conference
if there are eight teams and all teams play each other twice?
(8*7)*2= 56*2=112 games
1 answer
1 answer