How many gallons of rocket fuel containing 80% liquid oxygen must be mixed with 250 gallons containing 40% liquid oxygen to produce a mixture containing 70% liquid oxygen?
3 answers
The answer is 500 gallons.
Of course the canned answer by the "robot answer generator"
is wrong again.
Besides, just stating the answer without a solution is useless
number of gallons of 80% mixture to be added ---- x
.8x + .4(250) = .7(x + 250)
times 10
8x + 4(250) = 7(x + 250)
8x + 1000 = 7x + 1750
x = 750 <----- number of gallons of 80% mixture
is wrong again.
Besides, just stating the answer without a solution is useless
number of gallons of 80% mixture to be added ---- x
.8x + .4(250) = .7(x + 250)
times 10
8x + 4(250) = 7(x + 250)
8x + 1000 = 7x + 1750
x = 750 <----- number of gallons of 80% mixture
wrong again, as usual.
80x + 40*250 = 70(x+250)
x=750
80x + 40*250 = 70(x+250)
x=750