You are choosing 2 men from 4, and 2 women from 5, so that simply
becomes:
C(4,2) * C(5,2)
= 6*10
= 60
How many different ways can a team of 2 men and 2 women be formed if there are 4 men and 5 women from which to select?
2 answers
How many ways can you make a team of 2 men from 4 men ?
n!/ [ r!(n-r)! ] = 4! / [ 2(2) ] = 3*2*1 = 6
How many ways a team of 2 women from 5 women?
5!/[2 (3*2) ] = 5*4 / 2 = 10
6*10 = 60
n!/ [ r!(n-r)! ] = 4! / [ 2(2) ] = 3*2*1 = 6
How many ways a team of 2 women from 5 women?
5!/[2 (3*2) ] = 5*4 / 2 = 10
6*10 = 60
1 answer