so you would have 4 choice at first, then 3 choices next, then 2, then 1
4*3*2*1=24 possible combinations
How many different 6 letter "words" can be formed from the letters C,A,N,Y,O,N if:
O must be last, A must be first and repetitions aren't allowed. Here is how I set it up: A ? ? ? ? O (? Represents blanks) so 4!?
2 answers
agree