How far does an ant have to crawl to get from the base of the cone to the top of the hill? (This is the slant height, s, of the cone.) Answer the questions to find out.
Use 3.14 for π and round your answer to the nearest millimeter if necessary.
1. What is the height of the cone
2. Now that you have the height of the cone, how can you solve for the slant height, s?
3. How far does the ant crawl to get from the base of the cone to the top of the hill
5 answers
Please its urgent!! Please respond :(
the volume is 10,362 mm3 and radius 30 mm
as I told you an hour ago,
Since v = 1/3 πr^2 h, we have h = 3v/(πr^2) = 3*10362/(900π) = 10.99
So let's say h=11
Now, since s^2 = h^2 + r^2 = 121+900 = 1021
s = 31.95
or we could say s=32
Since v = 1/3 πr^2 h, we have h = 3v/(πr^2) = 3*10362/(900π) = 10.99
So let's say h=11
Now, since s^2 = h^2 + r^2 = 121+900 = 1021
s = 31.95
or we could say s=32
volume of cone = (1/3)π r^2 h
10362 = (1/3)π(15^2)(h)
h = (1/3)(10362/(225π)) = appr 15.35111
s^2 = 15.35111..^2 + 15^2 = ...
s = √......
I am sure you have a calculator
10362 = (1/3)π(15^2)(h)
h = (1/3)(10362/(225π)) = appr 15.35111
s^2 = 15.35111..^2 + 15^2 = ...
s = √......
I am sure you have a calculator
skip my response, I read it as diameter is 30 cm
(starting to think I am getting too old for this)
(starting to think I am getting too old for this)
3 answers