how does

secx(tanx + tan^2x- sec^2x)

simplified to
sec x (tanx -1)?

1 answer

you should have come across the identity
sec^2x = tan^2x + 1

(by dividing each term of sin^2 + cos^2x = 1 by cos^2x )

sub back in , and you got it
Similar Questions
  1. Evaluate the integral of(secx)^2 * (tanx)^3 *dx I started out with letting u=secx and du=secx*tanx*dx , but then I am kind of
    1. answers icon 1 answer
  2. tan(3x) + 1 = sec(3x)Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes
    1. answers icon 0 answers
  3. How do you verify:1.) sinxcosx+sinx^3secx=tanx 2.) (secx+tanx)/(secx-tan)=(secx+tanx)^2 I tried starting from the left on both
    1. answers icon 0 answers
  4. I can't find the integral for(tanx)^(6)*(secx)^(2) I tried splitting up tanx into (tanx)^2*(tanx)^4 and let the latter equal
    1. answers icon 0 answers
more similar questions