how does secx(tanx + tan^2x-

Evaluate the integral of(secx)^2 * (tanx)^3 *dx I started out with letting u=secx and du=secx*tanx*dx , but then I am kind of
1. 1 answer
2. asked by Dave
3. 747 views
tan(3x) + 1 = sec(3x)Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes
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2. asked by Jen
3. 3,886 views
How do you verify:1.) sinxcosx+sinx^3secx=tanx 2.) (secx+tanx)/(secx-tan)=(secx+tanx)^2 I tried starting from the left on both
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2. asked by Corin
3. 858 views
I can't find the integral for(tanx)^(6)*(secx)^(2) I tried splitting up tanx into (tanx)^2*(tanx)^4 and let the latter equal
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2. asked by Anonymous
3. 650 views
Int tanx sec^2x dx can be taken as (by putting it in form of Int xdx)Int secx.secx tanx dx=(sec^2x)/2 Int tanx.sec^2x
1. 3 answers
2. asked by Anonymous
3. 745 views
find the derivative of f(x)=tanx-4/secxI used the quotient rule and got (sec^2x-4)(secx)-(tanx-4)(cosx)/sec^2x but I'm pretty
1. 3 answers
2. asked by gnozahs
3. 746 views
1/tanx-secx+ 1/tanx+secx=-2tanxso this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
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2. asked by olivia
3. 1,340 views
How do i get left side to equal rs?(Tanx/1+secx)+(1+secx/tanx)=(2/sinx)
1. 1 answer
2. asked by Bobbie
3. 549 views
Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
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2. asked by Dave
3. 1,449 views
find dy/dxy=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may
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2. asked by amy
3. 1,551 views