How do you write 1.42 × 10–7 in standard form?

Answer 1

To write \(1.42 \times 10^{-7}\) in standard form, you need to express it as a decimal number. In standard form, this is done by moving the decimal point 7 places to the left because of the negative exponent (-7).

1. Start with the number: \(1.42\).

2. Move the decimal point 7 places to the left:

   • 1.42 -> 0.142 (moving it one place)
   • 0.142 -> 0.0142 (two places)
   • 0.0142 -> 0.00142 (three places)
   • 0.00142 -> 0.000142 (four places)
   • 0.000142 -> 0.0000142 (five places)
   • 0.0000142 -> 0.00000142 (six places)
   • 0.00000142 -> 0.000000142 (seven places)

Putting it all together, you have:

\[ 1.42 \times 10^{-7} = 0.000000142 \]

So, \(1.42 \times 10^{-7}\) in standard decimal form is \(0.000000142\).