How you use it depends upon the problem you are trying to solve.
It looks like you are trying to use conservation of energy to solve a problem of height and velocity of an object moving in a gravitational field, with a work or drag term (Fd) included. However the mvh on the left would have to be mv^2. Even more important, the v's and h's on the right and left sides shoule have different subscripts, since they would apply to different times along the trajectory.
How do you use this equation?
mgh+1/2mvh=mgh+1/2mv^2+Fd
1 answer
1 answer