2 sin 3x = 2[ 3 sin x-4 sin^3 x]
= 6 sin x - 8 sin^3 x
4 sin 2x = 4[ 2 sin x cos x ]
= 8 sin x cos x
so
6 sin x - 8 sin^3 x + 8 sin x cos x
2 sin x [ 3 - 4 sin^2 x + 4 cos x ]
How do you solve this problem?
y = 2sin 3x + 4sin 2x
I haven't done these types of problems for awhile and have forgotten how to do them.
1 answer