How do you solve this expression \sqrt[8]{v^{40}}!!! So basically it's v^40 divided by 8!!! When I typed v^5 on my homework it said that it was incorrect!!! I want to know what I did wrong!!! Pleaseeeeeeee helpppppppp!!! :(

Answer 1

I read \sqrt[8]{v^{40}} as (√8)(v^40)
In no way can that be interpreted as (v^40) ÷ 8 , I don't
even see a division sign in your expression

retype your expression without all those strange brackets
use v^40 to mean "v raised to the 40"

are you taking the square root of the whole thing, or just of 8 as you typed ?

Answer 2

I'm taking the square root of the whole thing!!! The problem is suppose to look something like this 8^√v^40!!! So 40 is inside of the square root thing and 8 is outside of the square root thing.

Answer 3

8^√v^40 or 8^√(v^40)

that would be 8^(v^2)