When I solve the inquality 2x^2 - 6 < 0,

Question

I get x < + or - sqrt(3)

So how do I write the solution?
Is it (+sqrt(3),-sqrt(3)) or (-infinity, sqrt(3))?
Why?

Thanks.

So would this work?

abs x < ( sqrt 3 )

or
- sqrt 3<x<sqrt 3

The answer is given (+sqrt(3),-sqrt(3))
I don't know the reason

fuji