How do you solve this equation? A piece of aluminum with a mass of 3.90g and a temperature of 99.3 degrees celcius is dropped into 10.0 g of a water at a temperature of 22.6 degrees celcius. What is the final temperature of the system?

Answer 1

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Answer 2

[masss Al x specific heat Al x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
Solve for Tfinal.

Answer 3

(3.9)*(0.9025J)*(Tfinal-99.3)+(10)*(4.184J)*(Tfinal-22.6)=0

(3.51975J)*(Tfinal-99.3)+(41.84J)*(Tfinal-22.6)=0

45.35975JTfinal-1295.095175=0

1295.095175/45.35975=28.6 degrees celsius