the aluminum displaces 12.9 kg of water with a volume of 12.9 L
expected volume (based on mass) ... 29.1 kg / 2.7 kg/L
cavity volume = actual volume - expected volume
A piece of aluminum is made with a cavity inside the aluminum. To find the volume of the cavity the piece of aluminum is weighed. In the air, the piece of aluminum has a mass of 29.1kg. In water, the piece of aluminum has an apparent mass of 16.2kg. What is the volume of the cavity? (Density of aluminum: 2700kg/m³)
(ANS: 2.1x10⁻³ m ³)
2 answers
V_Cavity + V_Obj = V_Displaced
Re-arranged =>
V_Cavity = V_Displaced - V_Obj
V_Obj = (Mass Object - Apparent Mass) / Density of Material
V_Obj = (29.1 kg - 16.2 kg) / 2700 kg/m3
V_Obj = 0.0047777777777778 m3
V_Displaced = (Mass Object - Displaced Mass) / Density of Material
V_Displaced = (29.1 kg - 12.9 kg) / 2700 kg/m3
V_Displaced = 0.006 m3
V_Cavity = V_Displaced - V_Obj = 0.006 m3 - 0.0047777777777778 m3
V_Cavity = 0.0012222222222222 m3 = 1.2E3
Re-arranged =>
V_Cavity = V_Displaced - V_Obj
V_Obj = (Mass Object - Apparent Mass) / Density of Material
V_Obj = (29.1 kg - 16.2 kg) / 2700 kg/m3
V_Obj = 0.0047777777777778 m3
V_Displaced = (Mass Object - Displaced Mass) / Density of Material
V_Displaced = (29.1 kg - 12.9 kg) / 2700 kg/m3
V_Displaced = 0.006 m3
V_Cavity = V_Displaced - V_Obj = 0.006 m3 - 0.0047777777777778 m3
V_Cavity = 0.0012222222222222 m3 = 1.2E3
0 answers