log (x+9) = log10 - logx
x+9 = 10/x
x^2 + 9x - 10 = 0
(x+10)(x-1) = 0
x = -1 or 1
But logx is undefined for x < 0, so x=1 is the only solution.
check: log(1+9) = log10 = 1 - log1 = 1-0 = 1
how do you solve
log (x+9) = 1 - log x
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