how do you solve 27 - 3^5x * 9^x2
2 answers
sorry it is 27= 3^5x x 9^x2
3^3 = 3^(5x) * [(3^2)^(x^2)] = 3^(2 x^2 + 5 x)
2 x^2 + 5 x - 3 = 0 ... (2 x - 1) (x + 3) = 0
x = 1/2 , x = -3
2 x^2 + 5 x - 3 = 0 ... (2 x - 1) (x + 3) = 0
x = 1/2 , x = -3
8 answers