got confused with this one too.
9^x =57
At first I square rooted but idk what to do now
How do you simplify this expression?
It gets confusing b/c of logs and exponents. Can someone help me explain how to do this.
8^log(8)x
4 answers
^ and log are inverse operations
x+8 - 8 = x
x/8 * 8 = x
(√x)^2 = x
log88x = x
8log8x = x
The thing that makes logs initially so confusing is the notation. If we had a cute symbol like + or / or √ things would be a lot easier.
The definition of log8x is that power of 8 which we need to get x.
Now, 9^x = 57 is a bit trickier. Recall that
log9N is the power of 9 you need to get N. So,
log957 is the power of 9 you need to get 57.
Taking log9 of both sides gives you
log99x = log957
But since log99x = x, you end up with
x = log957
x+8 - 8 = x
x/8 * 8 = x
(√x)^2 = x
log88x = x
8log8x = x
The thing that makes logs initially so confusing is the notation. If we had a cute symbol like + or / or √ things would be a lot easier.
The definition of log8x is that power of 8 which we need to get x.
Now, 9^x = 57 is a bit trickier. Recall that
log9N is the power of 9 you need to get N. So,
log957 is the power of 9 you need to get 57.
Taking log9 of both sides gives you
log99x = log957
But since log99x = x, you end up with
x = log957
So what is the simplified expression of 8^log(8)x? I got confused.
8^log(8)x = x
I stated it clearly as one of the examples.
Similarly, log(8) 8^x = x
I stated it clearly as one of the examples.
Similarly, log(8) 8^x = x