at the x-intercept, y = 0
so solve
x^2 + 2x - 3 = 0
The factors are obvious
how do you find the x-intercepts y=x^2+2x-3
5 answers
I still am confused, but let me try this
(x-1)(x+2) but I am not sure where to go from here
(x-1)(x+2) but I am not sure where to go from here
lYou factored it correcty.
The only way (x-1)(x+2) can equal zero is for one OR the other of the two factors to be zero.
Therefore x = 1 or -2.
The only way (x-1)(x+2) can equal zero is for one OR the other of the two factors to be zero.
Therefore x = 1 or -2.
oh makes sense! Because once you put them on the opposite side of the equation they would change fromeither positive to negative or negative to positive.
I think the factors are
(x+3)(x-1)
so solutions are
-3 and +1
(x+3)(x-1)
so solutions are
-3 and +1
1 answer