This problem can not be solved without the volume of NaOH used in the titration.
0.2079 g/molar mass H2C2O4.H2O = moles H2X2O4.H2O (note: you typed H2O one place and 2H2O another).
From the equation, moles NaOH = twice the moles of the oxalate.
Then MNaOH = moles NaOH/L NaOH.
How do you find the molarity(M) of NaOH in this reaction:
2NaOH(aq) + H2C2O4-H2O > Na2C2O4(aq) + 2H2O
The only given information is 0.2079g of H2C2O4-2H2O
3 answers
Hydrochloric acid is sold as a concentrated acqueous solution.
If the molarity of HCl is 12.0 and its density is 1.18 g/ml. calculate
A) MOLALITY
B)THE % BY MASS OF HCl in the solution
If the molarity of HCl is 12.0 and its density is 1.18 g/ml. calculate
A) MOLALITY
B)THE % BY MASS OF HCl in the solution
See you post above and the response by Bob Pursley. It isn't a good idea to piggy-back your post onto that of another.
3 answers