Asked by Morgan
How do you find the area of a pyrimid?
Answers
Answered by
MathMate
The base is a polygon with n sides.
Assume we know the side length, s, and the apotheme, a.
The area of the base is then
nas/2.
The slanted sides are triangles with base s and slant height h.
The area of the n slanted triangles are then
nhs/2
Thus, the total area of a pyramid with n sides is
A=nas/2+nhs/2=ns(a+h)/2
Assume we know the side length, s, and the apotheme, a.
The area of the base is then
nas/2.
The slanted sides are triangles with base s and slant height h.
The area of the n slanted triangles are then
nhs/2
Thus, the total area of a pyramid with n sides is
A=nas/2+nhs/2=ns(a+h)/2
Answered by
Reiny
The surface area of a square-based pyramid is the sum of
the area of the 4 congruent isosceles triangles + area of the base
(you will have to decide if the question includes the base area from the wording of the question)
the area of the 4 congruent isosceles triangles + area of the base
(you will have to decide if the question includes the base area from the wording of the question)
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