How do you factor 1/2x^3-x so that the zeroes can be found? Thank you-Adriana

Answer 1

I think you mean

1/(2x^3-x)

factoring the denominator
x(2x^2-1)= x(xsqrt2-1)(xsqrt2+1)

Answer 2

(1/2)x(x^2 - 2) = 0
x = 0 or x = ± √2

Answer 3

See how the same question can be interpreted in more than one way if you don't use brackets?

I read it as (1/2)x^3-x
bobpursley read it as 1/(2x^3-x)
or why not 1/(2x^3) - x ?